A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m. Find it volume. If $1 m^{3}$ wheat cost is ₹ 10 , then find total cost.

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Solution

Diameter of cone =10.5 m
Radius of cone (r)=5.25 m
Height of cone (h)=3 m
$Volume of cone = \frac{1}{3} π r^{2} h$
$= \frac{1}{3} \times \frac{22}{7} \times 5.25 \times 5.25 \times 3 = 86.625 m^{3}$
$Cost of 1 m^{3} of wheat = ₹ 10$
$Cost of 86.625 m^{3} of wheat = ₹ 10 \times 86.625$
$= ₹ 866.25$

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A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m. Find it volume. If 1m3 wheat cost is ₹ 10 , then find total cost.

Diameter of cone =10.5 m Radius of cone (r)=5.25 m Height of cone (h)=3 m Volume of cone =13πr2h =13×227×5.25×5.25×3=86.625 m3 Cost of 1 m3 of wheat =₹10 Cost of 86.625 m3 of wheat =₹10×86.625 =₹866.25

A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m. Find it volume. If $1 m^{3}$ wheat cost is ₹ 10 , then find total cost.