Question

A heap of wheat is in the form of a cone whose diameter is $10.5m$ and height is $3m$. Find its volume.
The heap is to be covered by canvas to protect it from the rain. Find the area of the canvas required (in $m^2$).
$[Assume\pi =\frac{22}{7}]$

• A. 99.825

Answer 1

The correct option is A 99.825
Radius ($r$) of the heap $=\left(\frac{10.5}{2}\right)m=5.25m$
Height ($h$) of heap = $3m$
Volume of the heap $=\frac{1}{3}\pi r^{2}h$
$=(\frac{1}{3}\times \frac{22}{7}\times (5.25{)}^2\times 3)m^3$
$=86.625m^3$
Therefore, the volume of the heap of wheat is $86.625m^3$.

Area of canvas required = CSA of cone
$=\pi rl=\pi r\sqrt{r^2+h^2}$
$=[\frac{22}{7}\times 5.25\times \sqrt{(5.25{)}^2+(3{)}^2}]m^2$
$=(\frac{22}{7}\times 5.25\times 6.05)m^2$
$=99.825m^2$
Therefore, $99.825m^2$ of canvas will be required to protect the heap from the rain.