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Question

A heat engine operates between 2100K and 700K. Its actual efficiency is 40%. What percentage of its maximum possible efficiency is this?

A
66.67%
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B
60%
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C
40%
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D
33.33%
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Solution

The correct option is B 60%
The efficiency of the engine is given as 1T2T1=17002100=113=66.67%.

But the actual efficiency if given as 40%.
Now to calculate how much percentage is the actual efficiency of its maximum possible efficiency we get 4066.67×100=60%.

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