Question

A heating device melts 60 g of ice in 1 minute. The power supplied by the device is____. (Latent heat of ice is 80 cal/gm)

• A. 4856 W
• B. 336 W
• C. 60 W
• D. 66 W

Answer 1

The correct option is B 336 W

Given:

Mass of ice $m$ = $60g$

Time taken, $t=60s$

Latent heat of ice, $L$ = $80cal/gm$

Work done by device, $W$ = Heat absorbed by ice

$=mL=60\times 80=4800cal$

$=4800\times 4.2J=20,160J$

$\therefore \text{Power,}P=\frac{W}{t}=\frac{20160}{60}=336W$