A heavy uniform chain lies on a horizontal table top. If the co efficient of friction between the chain and the table surface is 0.25 , then the maximum fraction of the length of the chain that can hang over one edge of the table is
20%
Chain has a mass ‘m’ and length ‘l’. Let a maximum length x of the chain project over the table. The length of the chain on the table is L – x. Then the pulling force due to the length x should be balanced by the limiting friction acting to the left.
ml×g=μml(l–x)g
x=μl1+μ
= 0.251.25
= 0.2
Therefore it is 20%