Given:
Inner radius of the hemispherical bowl = 5 cm
Thickness of the bowl = 0.25 cm
∴ Outer radius (r) of the hemispherical bowl = inner radius+thickness = (5 + 0.25) cm
= 5.25 cm
Outer CSA of hemispherical bowl =2πr2
=2×227×(5.25cm)2=173.25 cm2