Question

A hemispherical bowl is made of steel $0.25cm$ thick. The inner radius of the bowl is $5cm$. Find the outer curved surface area of the bowl.

Answer 1

It is given that

Inner radius of the bowl $=5cm$

Thickness of the bowl $=0.25cm$

External radius $=5+0.25=5.25cm$

We know that

Outer curved surface area of the bowl $=2\pi r^2$

By substituting the values

Outer curved surface area of the bowl $=2\times \frac{22}{7}\times {5.25}^2$

On further calculation

Outer curved surface area of the bowl $=2\times \frac{22}{7}\times 27.5625$

So we get

Outer curved surface area of the bowl $=173.25c{m}^2$.

Therefore, the outer curved surface area of the bowl is $173.25c{m}^2$.