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Question

A hemispherical bowl is made of steel $$0.25cm$$ thick. The inner radius of the bowl is $$5cm$$. Find the outer curved surface area of the bowl.


Solution

It is given that 

Inner radius of the bowl $$=5cm$$

Thickness of the bowl $$=0.25cm$$

External radius $$=5+0.25=5.25cm$$

We know that 

Outer curved surface area of the bowl $$=2\pi r^2$$

By substituting the values

Outer curved surface area of the bowl $$=2\times \dfrac{22}{7} \times 5.25^2$$

On further calculation

Outer curved surface area of the bowl $$=2\times \dfrac{22}{7} \times 27.5625$$

So we get 

Outer curved surface area of the bowl $$=173.25\ cm^2$$.

Therefore, the outer curved surface area of the bowl is $$173.25\ cm^2$$.

Mathematics
RS Agarwal
Standard IX

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