Question

A hemispherical bowl is made of steel $0.6m$ thick inside radius of bowl is $5m$. Find the volume of steel used in making the bowl.

Answer 1

r = 5cm

R = 5 + 0.6 = 5.6cm

V = $\frac{2}{3}\pi (R^3-r^3)$

V = $\frac{2}{3}\pi ({5.6}^3-5^3)$

V = $\frac{2}{3}\ast 3.14\ast (175.616-125)$

$V=105.95616$