A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm².

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Solution

Inner radius (r) of hemispherical bowl

Surface area of hemispherical bowl = 2πr²

Cost of tin-plating 100 cm² area = Rs 16

Cost of tin-plating 173.25 cm² area = Rs 27.72

Therefore, the cost of tin-plating the inner side of the hemispherical bowl is Rs 27.72.

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Question 5
A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of $R s . 16 p e r 100 c m^{2} . [A s s u m e π = \frac{22}{7}]$

Q. Note Take

π = \frac{22}{7}

, unless stated otherwise.
A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of ₹ 32 per 100 cm².

Q. A hemispherical bowl made of brass has inner diameter

10.5 c m

. Find the cost of tin-planting it on the inside at the rate of

16

per

100 c m^{2}

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A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm2.

Inner radius (r) of hemispherical bowl Surface area of hemispherical bowl = 2πr2 Cost of tin-plating 100 cm2 area = Rs 16 Cost of tin-plating 173.25 cm2 area = Rs 27.72 Therefore, the cost of tin-plating the inner side of the hemispherical bowl is Rs 27.72.

A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm².

Inner radius (r) of hemispherical bowl

Surface area of hemispherical bowl = 2πr²

Cost of tin-plating 100 cm² area = Rs 16

Cost of tin-plating 173.25 cm² area = Rs 27.72

Therefore, the cost of tin-plating the inner side of the hemispherical bowl is Rs 27.72.