A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs 4 per 100 cm².

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Solution

In the given problem, we have a hemispherical bowl.

Here,

Diameter of the bowl = 10.5 cm

So, Radius of the bowl = cm

So, the curved surface area of the bowl

Now, the rate of tin plating per 100 cm²= Rs 4

The rate of tin plating per 1 cm²= Rs

So, the cost of tin plating the bowl

= Rs 6.93

Therefore, the cost of tin plating the hemispherical bowl from inside is

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Question 5
A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of $R s . 16 p e r 100 c m^{2} . [A s s u m e π = \frac{22}{7}]$

Q. Note Take

π = \frac{22}{7}

, unless stated otherwise.
A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of ₹ 32 per 100 cm².

Q. A hemispherical bowl made of brass has inner diameter

10.5 c m

. Find the cost of tin-planting it on the inside at the rate of

16

per

100 c m^{2}

Question 5
A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of $R s . 16 p e r 100 c m^{2} . [A s s u m e π = \frac{22}{7}]$

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A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs 4 per 100 cm2.

A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs 4 per 100 cm².