A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs. $16$ per ${c m}^{2}$ .

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Solution

Radius of bowl = $\frac{10.5}{2} = 5.25$
Area of hemispherical bowl with radius $5.25$ is $2 π r^{2} = 2 π (5.25)^{2} = 173 c m^{2}$
Cost of coating $= 173 \times 16 = 2768$

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Question 5
A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of $R s . 16 p e r 100 c m^{2} . [A s s u m e π = \frac{22}{7}]$

Q. A hemispherical bowl made of brass has inner diameter

10.5 c m

. Find the cost of tin-planting it on the inside at the rate of

16

per

100 c m^{2}

Question 5
A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of $R s . 16 p e r 100 c m^{2} . [A s s u m e π = \frac{22}{7}]$

Q. Note Take

π = \frac{22}{7}

, unless stated otherwise.
A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of ₹ 32 per 100 cm².

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A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs. 16 per cm2.

Radius of bowl = 10.52=5.25Area of hemispherical bowl with radius 5.25 is 2πr2=2π(5.25)2=173 cm2Cost of coating =173×16=2768

A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs. $16$ per ${c m}^{2}$ .

Radius of bowl = $\frac{10.5}{2} = 5.25$
Area of hemispherical bowl with radius $5.25$ is $2 π r^{2} = 2 π (5.25)^{2} = 173 c m^{2}$
Cost of coating $= 173 \times 16 = 2768$