A hemispherical bowl made of brass has inner diameter $10.5 c m$ . Find the cost of tin-plating it on the inside at the rate of $R s 16$ per $100 c m^{2}$ .

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Solution

Given diameter=10.5cm
radius of bowl = $\frac{10.5}{2}$ = 5.15cm.
covred surfase area = $2 π r^{2}$
$= 2 \times 3.140 (5.25)^{2}$
CSA of bowl $= 173.09 c m^{2}$
cost of tin -plating $= 16 R S / 100 c m^{2}$
Total cost of plating = 1.73 $\times 16 = 27.68 R S$

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Q. Note Take

π = \frac{22}{7}

, unless stated otherwise.
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A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of $R s . 16 p e r 100 c m^{2} . [A s s u m e π = \frac{22}{7}]$

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. Find the cost of tin-planting it on the inside at the rate of

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A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm2.

Given diameter=10.5cmradius of bowl =10.52 = 5.15cm.covred surfase area =2πr2=2×3.140(5.25)2CSA of bowl =173.09cm2cost of tin -plating =16RS/100cm2Total cost of plating = 1.73×16=27.68RS

A hemispherical bowl made of brass has inner diameter $10.5 c m$ . Find the cost of tin-plating it on the inside at the rate of $R s 16$ per $100 c m^{2}$ .

Given diameter=10.5cm
radius of bowl = $\frac{10.5}{2}$ = 5.15cm.
covred surfase area = $2 π r^{2}$
$= 2 \times 3.140 (5.25)^{2}$
CSA of bowl $= 173.09 c m^{2}$
cost of tin -plating $= 16 R S / 100 c m^{2}$
Total cost of plating = 1.73 $\times 16 = 27.68 R S$