A hemispherical bowl made of brass has inner diameter of 10.5 cm. Find the cost of tin - plating it on the inside at the rate of Rs. 4 per $100 c m^{2}$ .

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Solution

$∴ R a d i u s (r) = \frac{10.5}{2} = 5.25 c m = \frac{525}{100} = \frac{21}{4} c m ∴ S u r f a c e a r e a o f i n n e r p a r t o f b o w l = 2 π r^{2} = 2 \times \frac{22}{7} \times \frac{21}{4} \times \frac{21}{4} c m^{2} = \frac{693}{4} c m^{2} R a t e o f t i n p l a t i n g = R s . 4 p e r 100 c m^{2} ∴ T o t a l c o s t = \frac{693 \times 4}{4 \times 100} = \frac{693}{100} = R s . 6.93$

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A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm².

Question 5
A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of $R s . 16 p e r 100 c m^{2} . [A s s u m e π = \frac{22}{7}]$

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π = \frac{22}{7}

, unless stated otherwise.
A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of ₹ 32 per 100 cm².

Q. A hemispherical bowl made of brass has inner diameter

10.5 c m

. Find the cost of tin-planting it on the inside at the rate of

16

per

100 c m^{2}

Question 5
A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of $R s . 16 p e r 100 c m^{2} . [A s s u m e π = \frac{22}{7}]$

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A hemispherical bowl made of brass has inner diameter of 10.5 cm. Find the cost of tin - plating it on the inside at the rate of Rs. 4 per 100cm2.

∴Radius(r)=10.52=5.25cm=525100=214cm∴Surface area of inner part of bowl=2πr2=2×227×214×214cm2=6934cm2Rate of tinplating=Rs.4per100cm2∴Total cost=693×44×100=693100=Rs.6.93

A hemispherical bowl made of brass has inner diameter of 10.5 cm. Find the cost of tin - plating it on the inside at the rate of Rs. 4 per $100 c m^{2}$ .