Question

A hockey ball at rest is hit by a stick, such that the force acts on the ball for 0.15 s. If the ball is of mass 100 g and covers a distance of 100 m in 2 seconds, find the magnitude of the force applied by the hockey stick. Assume no friction is acting on the ball while rolling on the ground?

Answer 1

Step1: Given Data:

Distance covered by the ball, when no frictional force is acting on it = 100 m

Initial velocity (u) = 0

Final velocity(v) = 50 m/s

Time(t) = 0.15 s

Step2: Calculation of force:

$$\begin{gathered} v=u+at \\ 50\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s$}\right.=0+a\times 0.15s \\ a=333.3\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s^2$}\right. \\ F=\frac{100}{1000}\left(kg\right)\times 333.3\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s^2$}\right. \\ F=33.33N \end{gathered}$$