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Question

A hollow cylinder has solid hemisphere inward at one end and on the other end it is closed with a flat circular plate. The height of water is 10 cm when flat circular surface is downward. Find the level of water, when it is inverted upside down, common diameter is 7 cm and height of the cylinder is 20 cm.

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Solution

Cylinder: Height = 20 \ cm, Radius = 3.5 \ cm

Sphere: Radius = 3.5 \ cm

Volume of water = \pi r^2 h = \frac{22}{7} \times (\frac{7}{2}) ^2 \times 10 = 385 \ cm^3

Let the height of water = h when cylinder is upside down

\Rightarrow \pi r^2 h = 385 + \frac{1}{2} \times \frac{4}{3} \pi \times 3.5^3

\Rightarrow \frac{22}{7} \times 3.5^2 \times h = 385 + \frac{1}{2} \times \frac{4}{3} \pi \times 3.5^3

\Rightarrow h = \frac{385 \times 7}{22 \times 3.5^2} + \frac{22 \times 3.5^3 \times 7}{3 \times 22 \times 3.5^2}

\Rightarrow h = 10 + \frac{7}{3} = 12 \frac{1}{3} \ cm


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