A hollow cylindrical iron pipe of length $1.4 m$ has bore radius $2.5 c m$ and thickness of the metal is $1 c m$ . What is the volume of the iron used in the pipe?

2640 {c m}^{3}

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2604 {c m}^{3}

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2460 {c m}^{3}

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NONE OF THE ABOVE

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Solution

The correct option is A $2640 {c m}^{3}$
R.E.F image
$r_{1} = 2.5 c m$
$r_{2} = r_{1} + t$
$\Rightarrow r_{2} = 3.5 c m$
$V = π (r_{1}^{2} - r_{1}^{2}) h$
$= π [(3.5)^{2} - (2.5)^{2}] 140 = 2640$

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A hollow cylindrical iron pipe of length 1.4m has bore radius 2.5cm and thickness of the metal is 1cm. What is the volume of the iron used in the pipe?

The correct option is A 2640cm3R.E.F image r1=2.5cmr2=r1+t⇒r2=3.5cmV=π(r21−r21)h=π[(3.5)2−(2.5)2]140=2640

A hollow cylindrical iron pipe of length $1.4 m$ has bore radius $2.5 c m$ and thickness of the metal is $1 c m$ . What is the volume of the iron used in the pipe?

The correct option is A $2640 {c m}^{3}$
R.E.F image
$r_{1} = 2.5 c m$
$r_{2} = r_{1} + t$
$\Rightarrow r_{2} = 3.5 c m$
$V = π (r_{1}^{2} - r_{1}^{2}) h$
$= π [(3.5)^{2} - (2.5)^{2}] 140 = 2640$