A hollow cylindrical vessel with negligible thickness has a base area of 4-3 sq ft and is 11-7 ft long- Find the capacity of this vessel-

Given: Base area = 4/3 sq ft Length = 11/7 ft We know that, Volume of cylinder = Base area nbsp;× Height = nbsp;4/3 nbsp;× 11/7 = nbsp; 44/21 cu. ft T ...

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Standard VII

Mathematics

Volume of a Right Circular Cylinder

A hollow cyli...

Question

A hollow cylindrical vessel with negligible thickness has a base area of $\frac{4}{3}$ sq ft and is $\frac{11}{7}$ ft long. Find the capacity of this vessel.

\frac{44}{7}

cu ft

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\frac{22}{21}

cu ft

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\frac{44}{21}

cu ft

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\frac{33}{28}

cu ft

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Solution

The correct option is C $\frac{44}{21}$ cu ft
Given:
Base area = $\frac{4}{3}$ sq ft
Length = $\frac{11}{7}$ ft

We know that,
Volume of cylinder
= Base area × Height
= $\frac{4}{3}$ × $\frac{11}{7}$
= $\frac{44}{21}$ cu. ft

Therefore,
Volume of the vessel is $\frac{44}{21}$ cu ft.

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A hollow cylindrical vessel with negligible thickness has a base area of 43 sq ft and is 117 ft long. Find the capacity of this vessel.

The correct option is C 4421 cu ftGiven: Base area = 43 sq ft Length = 117 ft We know that, Volume of cylinder = Base area × Height = 43 × 117 = 4421 cu. ft Therefore, Volume of the vessel is 4421 cu ft.

A hollow cylindrical vessel with negligible thickness has a base area of $\frac{4}{3}$ sq ft and is $\frac{11}{7}$ ft long. Find the capacity of this vessel.

The correct option is C $\frac{44}{21}$ cu ft
Given:
Base area = $\frac{4}{3}$ sq ft
Length = $\frac{11}{7}$ ft

We know that,
Volume of cylinder
= Base area × Height
= $\frac{4}{3}$ × $\frac{11}{7}$
= $\frac{44}{21}$ cu. ft

Therefore,
Volume of the vessel is $\frac{44}{21}$ cu ft.