Question

If the required volume of a cylindrical vessel is 16 cu ft and its base area is $\frac{13}{2}$ sq ft, the height of the vessel is .

• A. $\frac{8}{13}$ ft
• B. $\frac{32}{13}$ ft
• C. $\frac{16}{13}$ ft
• D. $\frac{13}{16}$ ft

Answer 1

The correct option is B $\frac{32}{13}$ ft

Given:
Required volume = 16 cu ft
Base area = $\frac{13}{2}$ sq ft

We know,
Volume = Base area $\times$ Height

$\Rightarrow$ 16 = $\frac{13}{2}$ $\times$ h

$\Rightarrow$ 16 ÷ $\frac{13}{2}$ = h $\times$ $\frac{13}{2}$ ÷ $\frac{13}{2}$

$\Rightarrow$ 16 $\times$ $\frac{2}{13}$ = h

$\Rightarrow$ h = $\frac{32}{13}$ ft

Therefore, the height of the vessel is $\frac{32}{13}$ ft.