A hollow wooden pipe has a thickness of $1.5 c m$ . It is $28 c m$ long and has an inner radius of $5.5 c m$ . Find the volume of wood required to make the pipe, assuming that it is open at both ends.

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Solution

Inner radius $= 5.5 ㎝$
Thickness $= 1.5 ㎝$
Outer radius $= 5.5 + 1.5 = 7 ㎝$
Volume of wood required $= π (R^{2} - r^{2}) \times h$
$= \frac{22}{7} (7^{2} - {(5.5)}^{2}) \times 28$
$= 88 (49 - 30.25)$
$= 1650 ㎤$

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A hollow wooden pipe has a thickness of 1.5 cm. It is 28 cm long and has an inner radius of 5.5 cm. Find the volume of wood required to make the pipe, assuming that it is open at both ends.

Inner radius=5.5㎝Thickness=1.5㎝Outer radius=5.5+1.5=7㎝Volume of wood required=π(R2−r2)×h=227(72−(5.5)2)×28=88(49−30.25)=1650㎤

A hollow wooden pipe has a thickness of $1.5 c m$ . It is $28 c m$ long and has an inner radius of $5.5 c m$ . Find the volume of wood required to make the pipe, assuming that it is open at both ends.

Inner radius $= 5.5 ㎝$
Thickness $= 1.5 ㎝$
Outer radius $= 5.5 + 1.5 = 7 ㎝$
Volume of wood required $= π (R^{2} - r^{2}) \times h$
$= \frac{22}{7} (7^{2} - {(5.5)}^{2}) \times 28$
$= 88 (49 - 30.25)$
$= 1650 ㎤$