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Question

A homogeneous ideal gaseous reaction AB2(g)A(g)+2B(g) is carried out in a 25 L flask at 27oC. The initial amount of AB2 was 1 mol and the equilibrium pressure was 1.9 atm. The value of KP is x×102. The value of x is ______. [R=0.08206dm3 atm K1 mol1]

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Solution

AB2(g) A(g) +2B(g)
Initial mole 1 0 0
At eq. 1x x 2x
At equilibrium,
nT=PVRTnT=1.9×250.08206×300=1.93Total number of moles at equilibrium:nT=1x+x+2x=1+2x1+2x=1.93 x=0.465

KP=PAP2BPAB2PA=XAPtotalKP=(0.4651.93×1.9)(0.931.93×1.9)2(0.5351.93×1.9) KP=73×102 atm2


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