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Question

A horizontal force F pulls a 10kg carton across the floor at a constant speed. If the coefficient of sliding friction between carton and floor is 0.50, the work done by F in moving the carton through 5m is

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Solution

Because horizontal speed is constant,the carton is in horizontal equilibrium.

Force applied will be equal to sliding friction

F = 0.5 x 10 x 9.8 = 49 N

W = F.x = 49 x 5 = 245 J

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