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Question

A rope of length L and mass M is being pulled on a rough horizontal floor by a constant horizontal force F=mg. The force is acting at one end of the rope in the same direction as the length of the rope. The coefficient of kinetic friction between rope and floor is 0.5. Then, tension at the midway of the rope is:

A
Mg4
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B
3Mg4
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C
Mg8
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D
Mg2
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Solution

The correct option is C Mg2

a = FμNM = Mg0.5MgM = g2

T - μMg2 = Ma2

T - Mg4 = Mg4

Hence T = Mg2

742478_237234_ans_7decf602fe9a4b73bf3c6092c0caf6c5.png

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