A horizontal straight wire 10m long extending from east to west is falling with a speed of 5.0 m/s at right angles to the horizontal component of earth's magnetic field $0.3 \times 10^{- 4}$ tesla. The emf induced across the ends of wire is

1.5 mV with higher potential at eastern end

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1.5 mV with higher potential at western end

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0.75 mV with higher potential at eastern end

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Zero

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Solution

The correct option is A 1.5 mV with higher potential at eastern end
$e = B_{H} l u$
$= 0.3 \times 10^{- 4} \times 10 \times 5$
$= 15 \times 10^{- 4}$
$= 1.5 \times 10^{- 3} v$
= 1.5 mV with higher potential at eastern end

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A horizontal straight wire 10m long extending from east to west is falling with a speed of 5.0 m/s at right angles to the horizontal component of earth's magnetic field 0.3×10−4 tesla. The emf induced across the ends of wire is

The correct option is A 1.5 mV with higher potential at eastern ende=BHlu =0.3×10−4×10×5 =15×10−4 =1.5×10−3v = 1.5 mV with higher potential at eastern end

A horizontal straight wire 10m long extending from east to west is falling with a speed of 5.0 m/s at right angles to the horizontal component of earth's magnetic field $0.3 \times 10^{- 4}$ tesla. The emf induced across the ends of wire is

The correct option is A 1.5 mV with higher potential at eastern end
$e = B_{H} l u$
$= 0.3 \times 10^{- 4} \times 10 \times 5$
$= 15 \times 10^{- 4}$
$= 1.5 \times 10^{- 3} v$
= 1.5 mV with higher potential at eastern end