A horse exerts a pull on a cart of 300 N so that the horse-cart system moves with a uniform speed of 18 km/h on a level road. Calculate the power developed by the horse to pull the cart in watts and also its equivalent in horse power

Open in App

Solution

$D e a r S t u d e n t, G i v e n, F = 300 N, v = 18 k m / h = 18 \times \frac{1000}{3600} = 18 \times \frac{5}{18} = 5 m / s W e h a v e, P o w e r, P = F \times v = 300 \times 5 = 1500 W W e k n o w, 1 h p = 746 W H e n c e, P = \frac{1500}{746} = 2.01 h p R e g a r d s .$

Suggest Corrections

Similar questions

When a horse exerts a force on cart , the cart exerts an equal and opposite force on the horse. Then how come the horse can manage to pull the cart ?

A horse is harnessed to a cart. If the horse tries to pull the cart, the horse must exert a force on the cart. By Newton's third law the cart must then exert an equal and opposite force on the horse. Since the two forces are equal and opposite, they must add to zero, so Newton's second law tells us that the acceleration of the system must be zero and therefore no matter how hard the horse pulls, it can never move the cart.

Q. When a horse pulls a cart, the force that helps the horse to move forward is the force exerted by

Q. Consider a cart being pulled by a horse with a constant velocity. The horse exerts force

{\to F}_{C / h}

on the cart . (The subscript indicates the force on the cart due to the horse.) The first subscript denotes the body on which the force act and the second due to which it acts.
Choose the correct statement (s):

Q. A 500 kg horse pulls a cart of mass 1500 kg along a level horizontal road with an acceleration of

1 m / s^{2}

. If the coefficient of sliding friction between the cart and ground is 0.2, then the force exerted by the horse on the cart in forward direction is: Assume limiting friction is acting)

Join BYJU'S Learning Program

A horse exerts a pull on a cart of 300 N so that the horse-cart system moves with a uniform speed of 18 km/h on a level road. Calculate the power developed by the horse to pull the cart in watts and also its equivalent in horse power

Dear Student,Given,F=300N, v=18km/h=18×10003600=18×518=5m/sWe have,Power,P=F×v=300×5=1500WWe know,1hp=746WHence,P=1500746=2.01hpRegards.

$D e a r S t u d e n t, G i v e n, F = 300 N, v = 18 k m / h = 18 \times \frac{1000}{3600} = 18 \times \frac{5}{18} = 5 m / s W e h a v e, P o w e r, P = F \times v = 300 \times 5 = 1500 W W e k n o w, 1 h p = 746 W H e n c e, P = \frac{1500}{746} = 2.01 h p R e g a r d s .$