A hot dog factory must ensure that its hot dogs are between $6 \frac{1}{4}$ inches and $6 \frac{3}{4}$ inches in length. If $h$ is the length of a hot dog from this factory, then which of the following inequalities correctly, expresses the accepted values of $h$ ?

∣ ∣ h - 6 \frac{1}{2} ∣ ∣ < \frac{1}{2}

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∣ ∣ h - 6 \frac{1}{4} ∣ ∣ < \frac{1}{2}

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∣ ∣ h - 6 \frac{1}{2} ∣ ∣ < \frac{1}{4}

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∣ ∣ h - 6 \frac{1}{4} ∣ ∣ > \frac{1}{4}

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Solution

The correct option is C $∣ ∣ h - 6 \frac{1}{2} ∣ ∣ < \frac{1}{4}$
$6.25 < h < 6.75 6.25 - 6.5 < h - 6.5 < 6.75 - 6.5 - 0.25 < h - 6 \frac{1}{2} < 0.25 ∣ ∣ h - 6 \frac{1}{2} ∣ ∣ < \frac{1}{4}$

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Similar questions

6^{\frac{1}{2}} \times 6^{\frac{1}{2}} \times 6^{\frac{3}{8}} \times 6^{\frac{1}{4}} \times . . . . . . . . .

6^{1 / 2} \times 6^{1 / 4} \times 6^{1 / 8} \times \dots \infty

6^{1 / 2} \times 6^{1 / 4} \times 6^{1 / 8}

\infty = 6

6^{\frac{1}{2}} \times 6^{\frac{1}{4}} \times 6^{\frac{1}{8}} . . . . . \infty = 6

6^{\frac{1}{2}} \times 6^{\frac{1}{4}} \times 6^{\frac{1}{8}} \times 6^{\frac{1}{16}} \times . .

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