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Electric Power

A house is fi...

Question

A house is fitted with $20$ lamps of $60 w a t t$ each, 10 fans consuming 0.5\ amp each and an electric kettle of resistance $110 o h m s$ the energy is supplied at $220 v o l t s$ of a cost $1 r u p e e$ per kilowatt hour. Monthly bill for running the appliances for $6 h o u r s$ a day $(t a k e 1 m o n t h = 30 d a y s)$

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Solution

we have,

$60 W \times 20 l a m p s = 1200 W$

$60 W \times 6 h o u r s = 360 W$

$220 W \times 10 f a n s = 2200 W$

$2200 W \times 6 h o u r s = 13.2 k W$

total $= 360 + 13.2 k = 13.56 k W$

total energy in 30 days $= 30 \times 13.5 k = 405 k W$

total cost $= 405 \times 10 = R s .4050$

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