A hunter in a valley is trying to shoot a deer on a hill. The distance of the deer along his line of sight is $10 \sqrt{181}$ meters and the height of the hill is $90$ meters. His gun has a muzzle velocity of $100 m / s$ . Minimum how many meters above the deer should he aim his rifle in order to hit it? $[g = 10 m / s^{2}]$ .

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Solution

Steps:
1) By Pythagoras Theorem,
Base ,x =
Target (deer ) is at :
y = 90m
x = 100 m
2) Equation of Trajectory /Equation of Path :
3) When
4) Hence ,there are two possibilites :
To hit the deer,hunter should aim his rifle 1810m or 10m above the deer to dircetly hit the deer.

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