A hydraulic press has a ram of 15 cm diameter and plunger is 1.5 cm. It is required to lift a weight of 1 tonne. The force required on plunger is

10kg

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100 kg

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1000 kg

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1 kg

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Solution

The correct option is A 10kg
Weight on the ram $F = m g = 1000 \times 10 = 10000$
Using Pascal's law $\frac{F}{A} = c o n s t a n t$ where $A = π D^{2}$
$∴$ $\frac{10000}{(15)^{2}} = \frac{F_{p}}{(1.5)^{2}}$ $⟹ F_{p} = 100$ N $= 10 k g f$

Thus, force required on plunger is $10 k g f$

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A hydraulic press has a ram of 15 cm diameter and plunger is 1.5 cm. It is required to lift a weight of 1 tonne. The force required on plunger is

The correct option is A 10kgWeight on the ram F=mg=1000×10=10000Using Pascal's law FA=constant where A=πD2∴ 10000(15)2=Fp(1.5)2 ⟹Fp=100 N =10 kgfThus, force required on plunger is 10 kgf

The correct option is A 10kg
Weight on the ram $F = m g = 1000 \times 10 = 10000$
Using Pascal's law $\frac{F}{A} = c o n s t a n t$ where $A = π D^{2}$
$∴$ $\frac{10000}{(15)^{2}} = \frac{F_{p}}{(1.5)^{2}}$ $⟹ F_{p} = 100$ N $= 10 k g f$

Thus, force required on plunger is $10 k g f$