Question

A hydrocarbon (A) of the formula $C_6{H}_{12}$ (does not have a three membered ring) does not react with $B{r}_2/H_{2}O$ but reacts with $B{r}_2/hv$ such that it can form 4 monobromo derivatives. The major product (B) obtained from photobromination, on treatment with alc. $KOH$ gives compound (C) which on reductive ozonolysis gives (D) of the formula $C_6{H}_{10}{O}_2$. Compound (D) reduces Tollens' reagent and gives compound (X). (X) gives iodoform test and produces compound (Y) after acidification. (Y) when heated with $P_2{O}_5$ forms a cyclic anhydride (Z).

List-I contains questions related to compounds of given Paragraph and List-II contains their answers.

$\begin{array}{cccc}& \text{List-I}& & \text{List-II}\\ \left(I\right)& \text{Which compound on oxidative ozonolysis gives (X)?}& \text{(P)}& \text{(Z)}\\ \left(II\right)& \text{Which compound on heating with dilute NaOH gives cyclohex-2-enone?}& \text{(Q)}& \text{(B)}\\ \left(III\right)& \text{Which compound is formed when cyclopentane-1, 2- dione is oxidized with}C{F}_{3}COOOH?& \text{(R)}& \text{(C)}\\ \left(IV\right)& \text{Which compound will give methylenecyclopentane when heated with sodium tert-butoxide?}& \text{(S)}& \text{(A)}\\ & & \text{(T)}& \text{(Y)}\\ & & \text{(U)}& \text{(D)}\end{array}$

Which of the following options has the correct combination considering List-I and List-II

• A. (I), (U) and (III), (T)
• B. (II), (U) and (I), (R)
• C. (IV), (U) and (II), (R)
• D. (I), (R) and (III), (T)

Answer 1

The correct option is B (II), (U) and (I), (R)