wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A hydrocarbon on ozonolysis gives one mole each of compounds A and B. Both A and B on reduction with sodium borohydride gives compounds C and D belonging to same homologous series. C has no position isomer whereas D has position isomer. A and B do not belong to the same homologous series. However, both A and B on oxidation with acidified KMnO4 give same compound. Identify the hydrocarbon.

A
3- Methyl-2-butene
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2,3-Dimethyl-1-butene
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2-Methyl-2-butene
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
3,4-Dimethyl-1-butene
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 2-Methyl-2-butene
Ozonolysis of alkenes form ketone or aldehydes. Their reduction with NaBH4 gives alcohols. C has no position isomer whereas D has position isomer.Thus C is a primary alcohol and D is a secondary alcohol. A is an aldehyde and B is a ketone. And the compound is 2methyl2butene
CH3(CH3)C=CHCH3(O3)CH3(CH3)C=O[A]+O=CHCH3[B]NaBH4CH3(CH3)CHOH[C]+HOCH2CH3[D]KMnO4CH3(CH3)CHOH+HOOCCH3

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Alkenes - Preparation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon