A hydrocarbon with formula C $_{8}$ H $_{18}$ gives one mono chloro derivative. The hydrocarbon can be :

n- Octane

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2-Methyl hepatane

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2,2,4-Trimethyl butane

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2,2,3,3,- Tetramethyl butane

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Solution

The correct option is C 2,2,3,3,- Tetramethyl butane
The structure of option D is shown in figure.

As all hydrogens are equivalent so only one monochloro derivative obtained.

Option D is correct.

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Similar questions

C_{8} H_{18}

C_{8} H_{18}

The hydrocarbon 2-methyl butane is an isomer of :
(a) n-pentane (b) n-butane (c) propane (d) iso-butane

[C_{4} H_{9} C l]

N a / e t h e r

(C_{4} H_{6} C l)

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