Question

A hydrocarbon with formula $C_8{H}_{18}$ gives one monochloro derivative. The hydrocarbon is:

• A. n-octane
• B. $2$ methyl heptane
• C. $2,2,4$ - trimethylpentane
• D. $2,2,3,3$, tetramethylbutane

Answer 1

The correct option is D $2,2,3,3$, tetramethylbutane

$C_8{H}_{18}\stackrel{C{l}_2}{\to }$ one monochlorintaion product.

From, the given reaction we can say that this $2,2,3,3tetramethylbutane$ give only one chlorination product as chlorine is added to one of the $-C{H}_3$ group.