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Standard XII
Chemistry
Cyanide
A hydrocarbon...
Question
A hydrocarbon with the minimum number of carbon atoms, capable of showing both geometrical and optical isomerism is (a) 3-methylpentene (b) 3-methylpent-2-ene (c) 4-methylhex-2-ene (d) 4-methylhept-3-ene
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Similar questions
Q.
The d and l isomer of [Co(en)
3
]
3+
are type of:
Q.
Match list-I (Cooordination Compounds) with list-II (Type of Isomerism) and select the correct answer using the codes given below :
List-I
List-II
A.
C
o
(
N
H
3
)
4
C
l
2
1.
Optical isomerism
B.
C
i
s
−
C
o
(
e
n
)
3
C
l
2
2.
Ionization Isomerism
C.
C
o
(
e
n
)
2
(
N
O
)
2
C
l
S
C
N
3.
Co-ordination Isomerism
D.
C
o
(
N
H
3
)
6
C
r
(
C
N
)
6
4.
Geometrical Isomerism
Q.
Draw the structures of the following organic halogen compounds:
(i)
4
−
tert-buty
−
3
−
idoheptane
(ii)
4
−
bromo
−
3
−
methylpent
−
2
−
ene
Q.
Trans -3 methylpent-2-ene is:
Q.
Geometrical isomerism is possible in case of -
a) Pent-2-ene
b) Ethene
c) Butane
d) Hex-3-ene
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Standard XII Chemistry
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