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Question

A hydrogen atom in ground state absorbs 10.2 eV of energy. The orbital angular momentum of the electron is increased by

(a) 1.05 × 10−34 J s
(b) 2.11 × 10−34 J s
(c) 3.16 × 10−34 J s
(d) 4.22 × 10−34 J s

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Solution

(a) 1.05 × 10−34 J s

Let after absorption of energy, the hydrogen atom goes to the nth excited state.

Therefore, the energy absorbed can be written as
10.2=13.6×112-1n210.213.6=1-1n21n2=13.6-10.213.61n2=3.413.6n2=4n=2

The orbital angular momentum of the electron in the nth state is given by
Ln=nh2π
Change in the angular momentum, L=2h2π-h2π=h2π
L=1.05×10-34 Js

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