Question

A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl of $pH=10$ and by passing hydrogen gas around the platinum wire at $1$ atm pressure and ${25}^{\text{0}}C$ Temperature. The oxidation potential of electrode would be:

• A. 1018 V
• B. 0.059 V
• C. 0.59 V
• D. 0.118 V

Answer 1

The correct option is C 0.59 V

As we know,
$\frac{1}{2}{H}_2\left(g\right)\to H^{+}+e^{-}$

$E_{o.p.}=E_{o.p.}^{\circ }-\frac{0.059}{n}\log \frac{\left[H^{+}\right]}{{\left(P_{H_2}\right)}^{1/2}}$

$E_{o.p.}=E_{o.p.}^{\circ }-\frac{0.059}{1}\log \frac{\left[{10}^{-10}\right]}{{\left(1\right)}^{1/2}}$

$(pH=10,pH=-log[H^{+}],[H^{+}]={10}^{-10}M)$

$E_{o.p.}=0.59V$