Question

A hydrogen-like atom in ground state absorbs 'n' photons having the same energy and it emits exactly 'n' photons when the electronic transition takes place. Then, the energy of the absorbed photon may be:

• A. 91.8 eV
• B. 40.8 eV
• C. 48.4 eV
• D. 54.4 eV

Answer 1

Answer: (A), (B)

91.8 eV
40.8 eV

Since it absorbs 'n' photons and it also emits exactly n-photons, therefore, the transition must have taken place from 1 to 2.
Energy of photon $=10.2\times Z^2$ , where Z $=$ 1,2,3,4.