Question

An electron in hydrogen atom after absorbing an energy photon jumps from energy state $n_1$ to $n_2$. Then it returns to ground state after emitting six different wavelengths in emission spectrum. The energy of emitted photons is either equal to less than the absorbed photons. The $n_1$ and $n_2$ are

• A. $n_2=4,n_1=3$
• B. $n_2=5,n_1=3$
• C. $n_2=4,n_1=1$
• D. $n_2=5,n_1=1$

Answer 1

The correct option is C $n_2=4,n_1=1$

From $n_2=4$,

6 lines are obtained in emission spectrum.

Now, $E_{4-2}=E_{absorbed}$

$F_{4-3}<E_{absorbed}$

and $E_{4-1},E_{3-1},E_{2-1}>E_{absorbed}$

Hence, $n_1=2$ and $n_2=4$