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Question

An electron in hydrogen atom after absorbing energy photons can jump between energy states n1 and n2(n2>n1). Then it may return to ground state after emitting six different wavelengths is emission spectrum. The energy of emitted photons is either equal to, less than or greater than the absorbed photons. Then n1 and n2 are

A
n2=4,n1=3
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B
n2=5,n1=3
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C
n2=4,n1=2
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D
n2=4,n1=1
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Solution

The correct option is A n2=4,n1=3
Given- electron can jump to ground state emitting photons of six different wavelengths. n2(n21)2=6 on solving, we get n2=4

Now, we know that Energy of photon is given by- E=13.6[1n211n22]eVE=13.6[1n21116]eV

For minimum energy of the photon- we have ,n21<16 for maximum value of (n1)n1<4n1=3 we get ,n1=3 & n2=4 Hence , opt (a) is correct.

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