$A$ in the above sequence of reactions is:

{C a C}_{2}

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B_{4} C_{3}

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S i C

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{A l}_{4} C_{3}

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Solution

The correct option is D ${A l}_{4} C_{3}$
Oxidation of 1 mole of 2-butene with acidified potassium permanganate gives 2 moles of acetic acid.
When acetic acid is heated with soda lime ( $N a O H + C a O$ ), carbon dioxide is lost to produce methane (compound $Y$ ).
Methane can also be produced by hydrolysis of beryllium carbide or aluminium carbide.
$A l_{4} C_{3} + 12 H_{2} O \to 4 A l (O H)_{3} + 3 C H_{4}$
Thus, $A$ in the above sequence of reactions is aluminium carbide or ${A l}_{4} C_{3}$ .

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