Question

$A$ is $75\%$ more than $B,$ $C$ is $\frac{3}{4}$ of $A$ and $D$ is $65\%$ more than $C$. What is the percentage of $B$ is $D$

• A. $126.11\%$
• B. $291.81\%$
• C. $126.56\%$
• D. $216.56\%$

Answer 1

Answer: (D)

$216.56\%$

$A=B+\frac{75}{100},B=\frac{175}{100}B$

$C=\frac{3}{4}A$

$D=C+\frac{65}{100}C=\frac{165C}{100}$

$\frac{D}{B}=\frac{\frac{165C}{100}}{\frac{100A}{175}}=\frac{\frac{165}{100}\cdot \frac{3}{4}A}{\frac{100A}{175}}=\frac{175\times 165\times 3A}{4\times 100\times 100\times A}=2.165$

So $\frac{D}{B}\times 100=2.165\times 100$ $=216.5\%$.