A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C?
A
9,46
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B
9,50
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C
10,46
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D
10,50
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Solution
The correct option is C9,50 We have : A=3B ...(i) and C−4=2(A−4) ...(ii) Also, A+4=31 or A=31−4=27. Putting A=27 in (i), we get: B=9. Putting A=27 in (ii), we get C=50.