A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?

3.6 sec

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18 sec

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36 sec

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72 sec

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Solution

The correct option is D 36 sec
Speed of train relative to jogger = $(45 - 9)$ km/hr = $36$ km/hr

$= (36 \times \frac{5}{18}) m / s e c$

= $10$ m/sec.

Distance to be covered = $(240 + 120) m = 360 m .$

$∴$ Time taken $= (\frac{360}{10}) s e c = 36 s e c .$

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A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?

The correct option is D 36 secSpeed of train relative to jogger = (45−9) km/hr = 36 km/hr=(36×518)m/sec= 10 m/sec.Distance to be covered = (240+120)m=360m.∴ Time taken =(36010)sec=36sec.

The correct option is D 36 sec
Speed of train relative to jogger = $(45 - 9)$ km/hr = $36$ km/hr

$= (36 \times \frac{5}{18}) m / s e c$

= $10$ m/sec.

Distance to be covered = $(240 + 120) m = 360 m .$

$∴$ Time taken $= (\frac{360}{10}) s e c = 36 s e c .$