A train $110$ metres long is running with a speed of $60$ kmph. In what time will it pass a man who is running at $6$ kmph in the direction opposite to that in which the train is going?

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Solution

Speed of train relative to man $= (60 + 6) k m / h r = 66 k m / h r$

$= 66 \times \frac{5}{18} m / s e c = \frac{55}{3} m / s e c$

Time taken to pass the man $= 110 \times \frac{3}{55} s e c = 6 s e c$

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A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

Speed of train relative to man =(60+6)km/hr=66km/hr=66×518m/sec=553m/sec Time taken to pass the man =110×355sec=6sec

A train $110$ metres long is running with a speed of $60$ kmph. In what time will it pass a man who is running at $6$ kmph in the direction opposite to that in which the train is going?

Speed of train relative to man $= (60 + 6) k m / h r = 66 k m / h r$

$= 66 \times \frac{5}{18} m / s e c = \frac{55}{3} m / s e c$

Time taken to pass the man $= 110 \times \frac{3}{55} s e c = 6 s e c$