A train 125 m long passes a man running at 5 kmph in the same direction in which the train is going in 10 seconds Find the speed of the train ( in kmph)

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Solution

Speed of the train relative to man = $(\frac{125}{10}) m / s e c = (\frac{25}{2}) m / s e c = (\frac{25}{2} \times \frac{18}{5}) k m / h r = 45 k m / h r$ d
Let the speed of the train be x kmph Then relative speed = $(x - 5) k m / h r$
$∴ x - 5 = 45$
$x = 50 k m / h r$

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A train 125 m long passes a man running at 5 kmph in the same direction in which the train is going in 10 seconds Find the speed of the train ( in kmph)

Speed of the train relative to man = (12510)m/sec=(252)m/sec=(252×185)km/hr=45km/hrdLet the speed of the train be x kmph Then relative speed =(x−5)km/hr∴x−5=45x=50km/hr

Speed of the train relative to man = $(\frac{125}{10}) m / s e c = (\frac{25}{2}) m / s e c = (\frac{25}{2} \times \frac{18}{5}) k m / h r = 45 k m / h r$ d
Let the speed of the train be x kmph Then relative speed = $(x - 5) k m / h r$
$∴ x - 5 = 45$
$x = 50 k m / h r$