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Question

# A juggler keeps on moving four balls in air throwing the balls after regular intervals. When one ball leaves his hand (speed =20ms−1), the position of other balls (height in metre) will be :(Take g=10ms−2)

A
10,20,10
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B
15,20,15
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C
5,15,20
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D
5,10,20
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Solution

## The correct option is A 15,20,15Time taken by the small ball to return to the hands of the juggler is 2vg=2×2010=4s. So, he is throwing the balls after 1s each. Let at some instant, he throws the ball number 4. Before 1s of throwing it, he throws ball 3. So, the height of ball 3 ish=ut−12gt2h3=20×1−12(10)(1)2=15mBefore 2s, he throws ball 2. So, the height of ball 2 ish2=20×2−12×10(2)2=20mBefore 3s, he throws ball 1. So, the height of ball 1 ish1=20×3−12×10(3)2⇒h1=15m

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