Question

A juggler keeps n balls going with one hand, so that at any instant, (n-1) balls are in air and one ball in the hand. If each ball rises to a height of x metres, the time for each ball to stay in his hand is

A
1n12xg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2n12xg
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2n2xg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1n2xg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 2n−1√2xgLet u be the initial velocity of the ball while going upwards.The final velocity of the ball at height x is, v=0Using the relation; v2=u2+2as we have,0=u2−2gx⟹u=√2gxIf t is the time taken by the ball in going up through distance x, then 0=u+(−g)t⟹t=ug​Total time after which the ball comes into the hand is :T=2t=2ug=2√2xgDuring time T, (n−1) balls will be in air and one ball will be in hand.TIme of stay for each ball in hand , =Tn−1=2√2xgn−1=2(n−1)√2xgHence, the correct option is (B)

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Motion Under Constant Acceleration
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program