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Question

# A juggler keeps 5 balls going with one hand , so that at any instant, 4ball in the hand. If each ball rises to a height of 20m, then the time for which each ball stays in the hand is (g=10m/s2)

A
1.0s
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B
1.5s
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C
2.0s
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D
4.0s
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Solution

## The correct option is A 1.0sLet ′n′ be the initial velocity of the ball while going upwards The final velocity of ball at height in 20 V+0V2=u2+2asO=u2+2asu=√2gx=g=√2×10×20u=20If ′t′ in taken be the ball going up through distance 20 mO=u+(−g)t or t=u/g=2010=2sec=2secTotal time after which the ball comes into hand T=2t=2ug=2g√2g20=22√2×20g=2√2×20g=2×2=4secDuring T1 4 ball will be in air and one ball in hand for one ball in handT4=44=1secTime for 4 balls 4sec one ball 1sec

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