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Question

A juggler keeps 5 balls going with one hand , so that at any instant, 4ball in the hand. If each ball rises to a height of 20m, then the time for which each ball stays in the hand is (g=10m/s2)

A
1.0s
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B
1.5s
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C
2.0s
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D
4.0s
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Solution

The correct option is A 1.0s
Let n be the initial velocity of the ball while going upwards
The final velocity of ball at height in 20 V+0
V2=u2+2as
O=u2+2as
u=2gx=g
=2×10×20
u=20
If t in taken be the ball going up through distance 20 mO=u+(g)t or t=u/g=2010=2sec
=2sec
Total time after which the ball comes into hand
T=2t=2ug=2g2g20=222×20g=22×20g
=2×2
=4sec
During T1 4 ball will be in air and one ball in hand for one ball in hand
T4=44=1sec
Time for 4 balls 4sec one ball 1sec

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