A juggler maintains four balls in motion, making each of them to rise a height of $20 m$ from his hand. What time interval should he maintain, for the proper distance between them? ( $g = 10 m / s^{2}$ )

3 s

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\frac{3}{2}

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1 s

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2 s

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Solution

The correct option is C $1 s$
For each ball-
$v^{2} - u^{2} = 2 a s$
$- u^{2} = 2 (- 10) 20$
$u = 20 m / s$
also
$v = u + a t$
$0 = 20 - 10 t$
$t = 20 s e c$
The ball has to return to his hand-
so total time is 4 seconds,
so each ball must be thrown at interval of $\frac{4}{4} = 1 s e c$ to maintain proper distance.

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A juggler maintains four balls in motion, making each of them to rise a height of 20m from his hand. What time interval should he maintain, for the proper distance between them? (g=10m/s2)

The correct option is C 1sFor each ball-v2−u2=2as−u2=2(−10)20u=20m/salso v=u+at0=20−10tt=20secThe ball has to return to his hand-so total time is 4 seconds,so each ball must be thrown at interval of 44=1sec to maintain proper distance.

A juggler maintains four balls in motion, making each of them to rise a height of $20 m$ from his hand. What time interval should he maintain, for the proper distance between them? ( $g = 10 m / s^{2}$ )