Question

A juggler throws balls into the air. He throws one whenever the previous one is at its highest point. How high do the balls rise if he throws n balls in each second. Acceleration due to gravity is g.

Answer 1

Juggler throws the ball into the air with ball having initial velocity = u

At the highest point of its path velocity will be zero as at maximum height velocity =0

So final velocity=0

According to question juggler throws a ball each second so for "n" balls
time taken to reach highest position (t)= 1/n

v=u+gt

0=u-g/n

-u=-g/n

u=g/n


S= ut-gt²/2

S=u/n-g/2n²

But u=g/n

S= g/n²-g/2n²

S=g/2n²