Question

A kite is flying at an inclination of ${60}^{\circ }$ with the horizontal. If the length of the thread is $120\text{m},$ then the height at which kite is:

• A. $60\sqrt{3}\text{m}$
• B. $60\text{m}$
• C. $\frac{60}{\sqrt{3}}\text{m}$
• D. $120\text{m}$

Answer 1

The correct option is A $60\sqrt{3}\text{m}$

Let at point $A$ kite is flying at a height $AB$ equal to $h.$

In $△ABC,$

$\begin{array}{cc}\sin {60}^{\circ }& =\frac{AB}{AC}\\ & \\ \frac{\sqrt{3}}{2}& =\frac{h}{120}\\ & \\ h& =\frac{120\times \sqrt{3}}{2}\\ & \\ & =60\sqrt{3}\text{m}\end{array}$

Hence, the kite is flying at the height of $60\sqrt{3}\text{m}.$